For the purpose of the investigation into the wear-resisting property of the austenitic high manganese steel, the wear rate per unit load(M) and the friction coefficient(f) were measured using the wear tester manufactured to simulate the abrasive condition.
Hardness of the bulk ($H_B$) and the abraded surface ($H_{A.S}$) and the metallographic structure were also studied in relation to the abrasive wear resistance of the steel.
It is shown that the wear rate per unit load(M) is related with each of the bulk hardness and the abraded surface hardness as follow expressions,
1) $M\times10^5=(14.008\pm1.758)-(0.0291\pm0.0046)H_{A.S} mg/cm-kg$.
2) $M =\frac{24}{1000}(60)^{-n}\times\frac{1}{H_B} mg/cm-kg$.
Expression 1) is empirical while exprestion 2) is semiempirical formula which has a relation with the intrinsic property of the steel.
The relationships between M and f, f and $H_{A.S}$ are also obtained and they are expressed as follows respectively.
3) $M\times10^5=(11.385\pm0.184)f-(7.444\pm0.173) mg/cm-kg$
4) $f = (1.88114\pm0.5097)-(0.0255\pm0.0010) H_{A.S}$
On the view of microstructure of the steel, it is found that the initial grain size (r) has no effect on the wear-resisting property of the steel but the intercarbide spacing(d) has an marked influence on the M, and the obtained relationship is as follow:
5) $M\times10^5= (5.4\pm0.3) - (43.0\pm6.07)\frac{1}{\sqrt{d}} mg/cm-kg$.
Austonite 高Mn銅의 내마모성을 조사하기 위하여 abrasive마모시험기를 제작하여 단위하중당 마모율(M)과 마찰계수(f)를 측정하였다.
Bulk의 경도($H_B$), 마찰마모면의 경도($H_{A.S}$) 및 현미경조직도 내마모성과 관련하여 조사 하였다.
Bulk의 경도($H_B$), 마찰마모면의 경도($H_{A.S}$) 와 단위하중당 마모율(M)사이에는 각각 다음과 같은 관계가 성립함을 알았다.
1) $M\times10^5=(14.008\pm1.758)-(0.0291\pm0.0046)H_{A.S} mg/cm-kg$
2) $M =\frac{24}{1000}(60)^{-n}\times\frac{1}{H_B} mg/cm-kg$
n:가공경화계수
1)식은 실험식이며 2)식은 銅의 본래의 성질과 관계된 Semi-empirical식이다.
M과 f, f와 $H_{A.S}$도 관찰하였고 다음과 같은 실험식으로 나타낼 수 있었다.
3) $M\times10^5=(11.385\pm0.184)f-(7.444\pm0.173) mg/cm-kg$
4) $f = (1.88114\pm0.5097)-(0.0255\pm0.0010) H_{A.S}$
현미경 조직면에서 결정 도는 내마모성과 무관함을 알았고, 탄화물간 거리(d)는 현저한 영향을 미치며 그 관계는 다음과 같다.
$M\times10^5= (5.4\pm0.3) - (43.0\pm6.07)\frac{1}{\sqrt{d}} mg/cm-kg$
